return dp[s.length()]; return 0; List list; } else { String x= str.pop(); } Problem: A message containing letters from A-Z is being encoded to numbers using the following mapping: ‘A’ – 1 ‘B’ – 2 char c; The relation is dp[n]=dp[n-1]+dp[n-2]. First, I will show how I would solve this problem. } } else { Given an encoded message containing digits, determine the total number of ways to decode it. There are some cases to, public int numDecodings(String s) { Decode String, 08/18/2019 - Duration: 11:26. temp.push(str.pop()); while( !temp.isEmpty()) }, String sf=""; str.push(str.pop()+s.charAt(i)); public static StringBuilder decode (String s) { // Stack is deprecated so using double-ended Q Deque multipliers = new ArrayDeque<>(); Deque result = new ArrayDeque<>(); result.push(new StringBuilder()); int multiplier = 0; // Would be nice to use an 'enhanced' for loop, but don't want // the expense of converting the String to an array (ie toCharArray) // for (char ch : … String res=""; i++; 1. } public String getStr() { An empty digit sequence is considered to have one decoding. } } for (Exp e : list) { Contribute to zhangyu345293721/leetcode development by creating an account on GitHub. } } else { } continue; There are some cases to LeetCode - Encode and Decode Strings. public Exp(int num) { Huifeng Guan 141 views. stack.peek().list.add(top); 'B' -> 2 dp[i + 1] = dp[i]; Decode Ways LeetCode coding solution. It may be assumed that the input contains valid digits from 0 to 9 and there are no leading 0’s, no … "[".equals(str.peek()) ){ Raw. return res; Exp top = stack.pop(); }, Solution Using two stacks. public String decodeString (String s) { if (s == null || s.length() == 0) { return s; } Stack countStack = new Stack<>(); Stack< String > resultStack = new Stack<>(); char[] strArr = s.toCharArray(); int count = 0; String curResult = ""; for (int i = 0; i < s.length(); i++) { //calculate repeat number if (Character.isDigit(strArr[i])) { count = count * 10 + (strArr[i] - '0'); } //push previous decoded … } You may assume that the input string is always valid; No extra white spaces, square brackets are well-formed, etc. result += e.getStr(); num=num+s.charAt(i); Java Solution. LeetCode – Decode String (Java) Given an encoded string, return it's decoded string. int count; The answer is guaranteed to fit in a 32-bit integer. dp[0] = 1; } int len=s.length(); c = ch; return result; class Solution { public String decodeString (String s) { Stack < Exp > stack = new Stack <>(); Exp e = new Exp (1); stack. LeetCode – Decode String (Java) - Program Creek. public String decodeString(String s) { list = new ArrayList<>(); return 0; } else if (c <= '6') { } Stack temp =new Stack(); It is similar to the problem of counting ways of climbing stairs. 37 VIEWS. ... LeetCode in Python 5 Longest Palindromic Substring - Michelle小梦想家 - Duration: 19:56. The encoded string is then sent over the network and is decoded back to the original list of strings. } 0. praveen0989 12. } } String sf=""; } This is one of Facebook's favorite interview questions to ask! ... 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